State the principle of floatation. A solid of density 200 $k g / m^{3}$ is dropped on the surface of water. What would be its apparent weight?

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Solution

archimedes principle states that the upward buoyant force exerted on the body immersed in the liquid either submerged partially or fully is equal to the weight of the fluid that body displaces and acts in the upward direction at the center of the mass to the displaced fluid

given $w = 0.02 g N$
$v = \frac{w}{d g} = 1.02 \times 10^{- 5}$
$B = v q g = 0.0102$
apparent weight= $w - B = 0.02 - 0.0102 = 0.0098$

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State the principle of floatation. A solid of density 200 kg/m3 is dropped on the surface of water. What would be its apparent weight?

State the principle of floatation. A solid of density 200 $k g / m^{3}$ is dropped on the surface of water. What would be its apparent weight?