Question

State the whether given statement is true or false

Prove that $x^2+6x+15$ has no zero.

• A. True
• B. False

Answer 1

The correct option is A True

$x^2+6x+15$

$={(x+3)}^2+15-9$

$={(x+3)}^2+6$

Now ${(x+3)}^2\ge 0$

$\therefore {(x+3)}^2+6\ge 6$

$\therefore$ since it is greater than or equal top $6$, it can never be equal to $0$

Hence Proved