State True1 or False0-The curved surface area of a frustum of a cone is - l r1-r2 and l-h2- r1 -r2 2 where- r1 and r2 are the radii of the two ends of the frustum and h is the vertical height-

Curved Surface area of a frustum of a cone #160; =π l( r _ 1 + r _ 2 ) #160; where l #160; #160;is the slant height = √( h ^ 2 + ( r _ ...

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Surface Area of Combined Figures

State True1 o...

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State True(1) or False(0).

The curved surface area of a frustum of a cone is $π l (r_{1} + r_{2})$ and $l = \sqrt{h^{2} + {(r_{1} - r_{2})}_{1}^{2}}$ where, $r_{1} a n d r_{2}$ are the radii of the two ends of the frustum and $h$ is the vertical height.

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π (r_{1} + r_{2}) l

l = \sqrt{h^{2} + (r_{1} + r_{2})^{2}}

r_{1} a n d r_{2}

\frac{1}{3} π h [r_{1}^{2} r_{2}^{2} - r_{1} r_{2}],

r_{1}, r_{2}

l

r_{1}

r_{2}

= π (r_{1} + r_{2})

r_{1}

r_{2}

l

r_{1} a n d r_{2}

π l (r_{1} + r_{2}) + π (r_{1}^{2} + r_{2}^{2})

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