Question

State True = 1 or False = 2, Element formed from ${}_{92}^{238}U$ (group IIIB) by emission of 1$\alpha$-particle is placed in group IIIB.

Answer 1

Element formed from ${}_{92}^{238}U$ (group IIIB) by emission of 1$\alpha$-particle is placed in group IIIB.
${}_{92}^{238}U{\to }_{90}^{234}Th{+}_2^{4}He$
Both ${}_{92}^{238}U$ and ${}_{90}^{234}Th$ belong to actinide series.