State True or False.
$(3 a - 7 b - c)^{2}$ $= 9 a^{2} + 49 b^{2} + c^{2} - 42 a b + 14 b c - 6 c a$

True

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False

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Solution

The correct option is A True
$(3 a - 7 b - c)^{2} = (3 a)^{2} + (- 7 b)^{2} + (- c)^{2} + 2 (3 a) (- 7 b) + 2 (- 7 b) (- c) + 2 (- c) (3 a)$
$= 9 a^{2} + 49 b^{2} + c^{2} - 42 a b + 14 b c - 6 c a$

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Similar questions

If 3a - 7b = 26 and ab = 5, then the value of 9a² + 49b².

(b^{2} + c^{2} - a^{2}) tan A = (c^{2} + a^{2} - b^{2}) tan B

(a^{2} + b^{2} - c^{2}) tan C

a b (a^{2} + b^{2} - c^{2}) + b c (a^{2} + b^{2} - c^{2}) - c a (a^{2} + b^{2} - c^{2})

= (a^{2} + b^{2} - c^{2}) (a b + b c - c a)

C_{0} + C_{1} + C_{2} + \dots + C_{n} = 2^{n}

(3 a - 7 b - c)^{2}

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