State True or False.
$8 a^{3} + b^{3} + 12 a^{2} b + 6 a b^{2}$ $= (2 a + b) (2 a + b) (2 a + b)$

True

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False

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Solution

The correct option is A True
We have, $8 a^{3} + b^{3} + 12 a^{2} b + 6 a b^{2} = (2 a)^{3} + (b)^{3} + 6 a b (2 a + b)$
Using, $(a + b)^{3} = a^{3} + b^{3} + 3 a b (a + b)$
$= (2 a)^{3} + (b)^{3} + 3 (2 a) (b) (2 a + b)$
$= (2 a + b)^{3}$
$= (2 a + b) (2 a + b) (2 a + b)$

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Similar questions

8 a^{3} - b^{3} - 12 a^{2} b + 6 a b^{2}

= (2 a - b) (2 a - b) (2 a - b)

Factorise : 8a³ + b³ + 12a²b + 6ab²

(2 a + b)^{3}

8 a^{3} + 12 a^{2} b + 6 a b^{2} + b^{3}

8 a^{3} + b^{3} + 12 a^{2} b + 6 a b^{2}

Factorise: $8 a^{3} - b^{3} - 12 a^{2} b + 6 a b^{2}$

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