State True or False.
$a^{2} + b^{2} - 2 (a b - a c + b c)$ $= (a - b) {(a - b) + 2 c} = (a - b) (a - b + 2 c)$

True

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

False

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A True
We have, $a^{2} + b^{2} - 2 (a b - a c + b c) = a^{2} + b^{2} - 2 a b + 2 a c - 2 b c$
$= (a^{2} + b^{2} - 2 a b) + 2 a c - 2 b c$
$= (a - b)^{2} + 2 c (a - b)$
$= (a - b) {(a - b) + 2 c} = (a - b) (a - b + 2 c)$

Suggest Corrections

Similar questions

A = [\begin{matrix} 2 & - 1 0 & 1 \end{matrix}]

B = [\begin{matrix} 1 & 0 - 1 & - 1 \end{matrix}],

(A + B)^{2} = A^{2} + A B + B A + B^{2} = A^{2} + 2 A B + B^{2}

a^{8} - 2 a^{4} b^{4} + b^{8}

Question 61

In the following question, state whether the statement is True (T) or False (F):

$(a + b) (a - b) = a^{2} - b^{2}$

Simplify $\frac{a - b}{a} + \frac{a + b}{b}$

a^{2} - a b (1 - b) - b^{3}

(a - b) (a + b^{2})

Join BYJU'S Learning Program