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Question

State True or False.

(a+b)3+(b+c)3+(c+a)3−3(a+b)(b+c)(c+a) = 2(a3+b3+c3−3abc)

A
True
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B
False
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Solution

The correct option is A True
L.H.S:(a+b)3+(b+c)3+(c+a)33(a+b)(b+c)(c+a)
=(a3+3a2b+3ab2+b3)+(b3+3b2c+3bc2+c3)+(c3+3c2a+3ca2+a3)3(a+b)(bc+ba+c2+ca)
=(2a3+2b3+2c3+3a2b+3ab2+3b2c+3bc2+3c2a+3ca2)3(a+b)(bc+ba+c2+ca)
=(2a3+2b3+2c3+3a2b+3ab2+3b2c+3bc2+3c2a+3ca2)3(abc+ba2+ac2+ca2+b2c+b2a+bc2+abc)
=2a3+2b3+2c36abc
=2(a3+b3+c33abc)
=R.H.S

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