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Question

State True or False:
Addition of a6−4a4+6a, 5a6+5a4+6a, 12a6−10a is 18a6+a4+2a.

A
True
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B
False
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Solution

The correct option is A True
Wecanaddthecoefficientoflikepowersdirectly,a64a4+6a+5a6+5a4+6a+12a610a=(1+5+12)a6+(4+5)a4+(6+610)a=18a6+a4+2a

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