Addition of NH4Cl can precipitate Al(OH)3 from soluble Na[Al(OH)4].
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Solution
NH4Cl solution is acidic due to hydrolysis: NH4Cl+H2O⇌NH4OH+HCl. Hence, addition of NH4Cl solution precipitates Al(OH)3 when added to NaAl(OH)4Na[Al(OH)4]+HCl→NaCl+Al(OH)3↓+H2O