State True or False.
As the distance for an $s$ -orbital increases from the nucleus, the probability density of electron cloud decreases.

True

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False

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Solution

The correct option is A True
As the distance for s-orbital increases from the nucleus, volume increases according to $V \propto r^{3}$ but no of electron in s-orbital remain same so probability density decreases.

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Question 03

The probability density plots of 1s and 2s orbital are given in figure.

The density of dots in region represents the probability density of finding electrons in the region. On the basis of above diagram which of the following statements is incorrect ?

(a) 1s and 2s orbitals are spherical in shape

(b) The probability of finding electron is maximum near the nucleus

(d) The probability density of electrons for 2s orbital decreases uniformly as distance from the nucleus increases

Q. Assertion :An electron in an

s

-orbital has a non-zero probability of being found right at the nucleus. Reason:

l = 0

for

s

-orbitals and thus there is no orbital angular momentum to fling the electron away from the nucleus.

State True or False.

The value of

ψ_{1 s}^{2}

increases with increase in the distance of the electron from the nucleus.

Q. For 1s orbital of hydrogen atom, the radial electron probability has a maximum value from its nucleus, at a distance of:

State whether true or false.

As the distance of the planet from the sun increases, the period of revolution decreases.

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State True or False.As the distance for an s-orbital increases from the nucleus, the probability density of electron cloud decreases.

The correct option is A TrueAs the distance for s-orbital increases from the nucleus, volume increases according to V∝r3 but no of electron in s-orbital remain same so probability density decreases.

State True or False.
As the distance for an $s$ -orbital increases from the nucleus, the probability density of electron cloud decreases.

The correct option is A True
As the distance for s-orbital increases from the nucleus, volume increases according to $V \propto r^{3}$ but no of electron in s-orbital remain same so probability density decreases.