Question

State true or false: ${\left(\frac{-7}{9}\right)}^2÷\frac{49}{81}=-1$

• A. True
• B. False
• C. Ambiguous
• D. Data insufficient

Answer 1

The correct option is B False

${\left(\frac{-7}{9}\right)}^2÷\frac{49}{81}={\left(\frac{-1\times 7}{9}\right)}^2\times {\left(\frac{7}{9}\right)}^{-2}={\left(\frac{7}{9}\right)}^{2-2}=1$

Here, ${\left(\frac{-7}{9}\right)}^2={\left(\frac{7}{9}\right)}^2$

(As the square of $-ve$ sign number, will give a positive number)