Let ∠EBA=x and ∠EAB=y.Then, ∠EAB=∠FCB (Opposite angles of parallelogram)
Also, ∠EBA=∠CFB (∵CF||AB )
⇒∠AEB=∠CBF
Therefore by AAA Theorem of similarity,
ΔBCF and ΔBAE are similar.
ABCD is a parallelogram. The sides AB and AD are produced to E and F respectively, such that AB = BE and AD = DF.
Hence ΔBEC≅ΔDCF.
State whether the above statement is true or false.