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Question

State True or False-
E is a point on the side AD produced of a parallelogram ABCD and BE intersects CD at F. ABE is similar to CFB:

A
Always true
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B
May be true
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C
Information insufficient
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D
Always false
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Solution

The correct option is A Always true

Let EBA=x and EAB=y.
Then, EAB=FCB (Opposite angles of parallelogram)

Also, EBA=CFB (CF||AB )

AEB=CBF

Therefore by AAA Theorem of similarity,

ΔBCF and ΔBAE are similar.


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