Question

State True or False.
Expanded form of ${(x-\frac{2}{3}y)}^3=$$x^3-2x^{2}y+\frac{4x{y}^2}{3}-\frac{8}{27}{y}^3$

• A. True
• B. False

Answer 1

The correct option is A True

Formula used: $(a-b{)}^3=a^3-3a^{2}b+3a{b}^2-b^3$
Now, $(x-\frac{2}{3}y{)}^3=(x{)}^3-3\times (x{)}^2\times (\frac{2}{3}y)+3\times (x)\times (\frac{2}{3}y{)}^2-(\frac{2}{3}y{)}^3$
$=x^3-2x^{2}y+\frac{4}{3}x{y}^2-\frac{8}{27}{y}^3$