State True or False.
Fe $^{3 +}$ is paramagnetic.

True

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False

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Solution

The correct option is A True
$F e : [A r] 3 d^{6} 4 s^{2}$
$F e^{+ 3} : [A r] 3 d^{5} 4 s^{0}$
As it have 5 unpaired electron so it is paramagnetic in nature.

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Similar questions

_{3}

_{4}

_{2}

_{3}

\frac{2}{3}

\frac{4}{5}

\frac{41}{60}, \frac{42}{60}, \frac{43}{60}, \frac{44}{60}, \frac{45}{60}

(3 + \sqrt{3}) (3 - \sqrt{3})

= 6

{[{(\frac{3}{7})}^{2}]}^{3} = {(\frac{3}{7})}^{5}

\sqrt{3 + \sqrt{2}}

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