Question

State true or false:

If $21x^2-2x+\frac{1}{21}=0$, then the roots are $\frac{1}{21},\frac{1}{21}$.

• A. True
• B. False

Answer 1

The correct option is A True

Given: $21x^2-2x+\frac{1}{21}=0$

On simplifying we get, $441x^2-42x+1=0$

$441x^2-21x-21x+1=0$

$21x(21x-1)-1(21x-1)=0$

$(21x-1)(21x-1)=0$

$\therefore x=\frac{1}{21},x=\frac{1}{21}$

Hence, the statement is True.