Question

State true or false:

If $4(x-2{)}^2-x^2=(x+4{)}^2$, then $x=0$ or $x=10$.

• A. True
• B. False

Answer 1

The correct option is B False

Given equation is:

$4(x-2{)}^2-x^2=(x+4{)}^2$
$4x^2+16-16x-x^2=x^2+16+8x$
$2x^2-24x=0$
$x(x-12)=0$
$\therefore x=0,12$