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Integration of Piecewise Continuous Functions

State true or...

Question

State true or false:
If $6 x^{2} = x + 1$ , then $x$ is $\frac{1}{2}$ or $- \frac{1}{3}$ .

A

True

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B

False

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Solution

The correct option is A True
$6 x^{2} = x + 1$
$6 x^{2} - x - 1 = 0$
$6 x^{2} - 3 x + 2 x - 1 = 0$
$(3 x + 1) (2 x - 1) = 0$
$x = \frac{- 1}{3}, \frac{1}{2}$

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