CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Integration of Piecewise Continuous Functions

State true or...

Question

State true or false:
If $6 x^{2} = x + 1$ , then $x$ is $\frac{1}{2}$ or $- \frac{1}{3}$ .

A

True

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

B

False

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A True
$6 x^{2} = x + 1$
$6 x^{2} - x - 1 = 0$
$6 x^{2} - 3 x + 2 x - 1 = 0$
$(3 x + 1) (2 x - 1) = 0$
$x = \frac{- 1}{3}, \frac{1}{2}$

Suggest Corrections

thumbs-up

0

Similar questions

State true or false:

\frac{1}{x + 1} + \frac{1}{x - 2} = \frac{1}{x - 3}

x

5

0

.

State true or false:

x + 1 = \frac{6}{x}

x

2

3

.

State true or false:

\frac{x}{x - 1} + \frac{x - 1}{x} = 2 \frac{1}{2}

x

2

1

State true or false:

\frac{2}{3 x} = \frac{x - 1}{2 x - 1}

x

2 o r \frac{1}{3}

State true or false:

\frac{7}{3 x - 4} - \frac{2}{x + 2} = 1

x

3

- \frac{10}{3}

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Integration of Piecewise Functions

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Integration of Piecewise Continuous Functions

Standard XII Mathematics

Join BYJU'S Learning Program

CrossIcon