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Question

State true or false:

If a+2b+c=0; then
a3+8b3+c3=6abc

A
True
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B
False
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Solution

The correct option is A True
We know that,
(a+b+c)3=a3+b3+c3+3[(a+b+c)(ab+bc+ca)abc]
If a+b+c=0 then,
a3+b3+c3=3abc
Now,
a+2b+c=0
L.H.S=a3+8b3+c3
=3(a)(2b)(c)[Since a+2b+c=0]
=6abc

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