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B
False
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Solution
The correct option is A True We know that, (a+b+c)3=a3+b3+c3+3[(a+b+c)(ab+bc+ca)−abc] If a+b+c=0 then, a3+b3+c3=3abc Now, a+2b+c=0 L.H.S=a3+8b3+c3 =3(a)(2b)(c)[Since a+2b+c=0] =6abc