If the two angles of a triangle are unequal, then the greater angle has the larger side opposite to it.
A
True
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B
False
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Solution
The correct option is A True Given: △ABC, ∠ACB>∠ABC To Prove: AB>AC Construction: Make a point D on AB such that ∠ACD=∠ADC and join DC In △ACD, ∠ACD=∠ADC AD=AC (Sides opposite equal angles) But AB=AD+DB thus, AB>AD but AD=AC Hence, AB>AC Thus, sides opposite greater angles are larger