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Question

State True or False.
If x=322, then the value of x31x3 = 1402.

A
True
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B
False
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Solution

The correct option is A True

x=322
1x=1322
1x=3+22(322)(3+22)
=3+2232(22)2
=3+2298
=3+22
Now,
x1x=322(3+22)
=42
We know,
x21x2=(x+1x)22(x)(1x)
=(322+3+22)22
=622
=362
=34
Now,
x31x3=(x1x)[x2+1x2+(x)(1x)]
=(42)(34+1)
=(42)35
=1402


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