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B
False
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Solution
The correct option is A True x=3−2√2x−1x=3−2√2−13−2√2=(3−2√2)2−1(3−2√2)=9+8−12√2−13−2√2=16−12√23−2√2rationalizethedenominator,(3+2√2)(16−12√2)(3−2√2)(3+2√2)=48−36√2+32√2−489−8=−4√2