State True or False:
If $x = 6 a + 8 b + 9 c$ ; $y = 2 b - 3 a - 6 c$ and $z = c - b + 3 a$ ; then $x + y + z$ is $6 a + 9 b + 4 c$ .

True

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False

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Solution

The correct option is A True
$W e c a n d i r e c t l y a d d t h e c o e f f i c i e n t s o f l i k e v a r i a b l e s, x = 6 a + 8 b + 9 c; y = 2 b - 3 a - 6 c; z = c - b + 3 a x + y + z = 6 a + 9 b + 4 c$

Suggest Corrections

Similar questions

x = 6 a + 8 b + 9 c

y = 2 b - 3 a - 6 c

z = c - b + 3 a

2 x - y - 3 z

6 a + 17 b + 21 c

If x=6a+8b+9c;y=2b-3a-6c and z=c-b+3a ; find

(i) x+y+z (ii) x-y+z

(iii) 2x-y-3z (iv) 3y-2z-5x

(a - 2 b + 5 c) (a - b) - (a - b - c) (2 a + 3 c) + (6 a + b) (2 c - 3 a - 5 b)

19 c a - 37 a b - 19 a^{2}

x^{2} + y^{2} + z^{2} = 21 a^{2}, y z + z x - x y = 6 a^{2}, 3 x + y - 2 z = 3 a

a^{x} = b, b^{y} = c

c^{z} = a

x y z = 1

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