Question

State true or false:

In an isosceles triangle $ABC$, $\angle ABC={90}^o$, then $A{C}^2=2A{B}^2$.

• A. True
• B. False

Answer 1

The correct option is A True

$\angle ABC={90}^{\circ }$

opposite side to this angle will be larger side and it is $AC$

SInce, it is an isosceles triangle, hence, $AB=BC$

$A{C}^2=B{C}^2+A{B}^2$ (Pythagoras Theorem)
$A{C}^2=A{B}^2+A{B}^2$
$A{C}^2=2A{B}^2$