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Question

State true or false:

In parallelogram ABCD.E and F are mid-points of the sides AB and CD respectively. The line segments AF and BF meet the line segments ED and EC at points G and H respectively, then
triangles HEB and FHC are congruent.

A
True
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B
False
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Solution

The correct option is A True
Given: parallelogram ABCD, E and F are mid points of AB and CD respectively. DE and EC meet AF and BF respectively at G and H
Now, In HEB and HFC
EHB=FHC (vertically opposite angles)
EB=FC (Half lengths of equal sides)
HBE=HFC (Alternate angles for parallel sides AB and CD)
Thus, HEBHCF (AAS rule)

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