The correct option is
A True
In
△s, APB and ECB,
∠ABP=∠EBC (Common angle)
∠PAB=∠CEB (Corresponding angles of parallel lines)
∠APB=∠ECB (Third angle of the triangle)
Thus
△APB∼△ECB Hence,
ABEB=BPBC (Corresponding sides of similar triangles)
2=BPBCBP=2BCBP=2AD (BC = AD)
![198209_179105_ans_39ae61af74574d11a344325f27367926.png](https://search-static.byjusweb.com/question-images/toppr_ext/questions/198209_179105_ans_39ae61af74574d11a344325f27367926.png)