State True or False.
In the below figure, the length of BC= 4cm.

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Solution

False
Given that $O A ⊥ B C .$
Using Pythagoras' theorem in $△ O A B,$ we have
$O B^{2} = O A^{2} + A B^{2} .$
$⟹ 5^{2} = 3^{2} + A B^{2}$
$⟹ A B = 4 c m$
We know that the perpendicular drawn from the centre of a circle to the chord bisects the chord.
$⟹ A B = A C$
$⟹ B C = 2 \times A B = 2 \times 4 = 8 c m$ .

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