Question

State True or False.
In the below figure, the length of BC= 4cm.

Answer 1

False
Given that $OA\perp BC.$
Using Pythagoras' theorem in $△OAB,$ we have
$O{B}^2=O{A}^2+A{B}^2.$
$⟹5^2=3^2+A{B}^2$
$⟹AB=4cm$
We know that the perpendicular drawn from the centre of a circle to the chord bisects the chord.
$⟹AB=AC$
$⟹BC=2\times AB=2\times 4=8cm$.