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Question

State true or false:
In the following diagram, lines l,m and n are parallel to each other. Two transversals p and q intersect the parallel lines at points A,B,C and P,Q,R respectively as shown, then:
ABBC=PQQR

179408_29e4ffb050c04e2c8c0b395f91146b42.png

A
True
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B
False
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Solution

The correct option is A True
Given l||m||n and have two transversal lines p and q. They cut at A,B,C and P,Q,R respectively.
PX perpendicular to OA and AY perpendicular to OQ.
Since PX perpendicular to OA, PX is height of OPA and BAP
ar(OPA)=12bh=12×OA×PX
ar(BAP)=12bh=12×AB×PX
ar(BAP)ar(OPA)=12AB.PX12OA.PXar(BAP)arc(OPA)=ABOA ...(i)
Since AY perpendicular to OP. So, AY is the height of OAP and QAP
ar(OAP)ar(QAP)=12×PQ×AY12×OP×AY=PQOP...(ii)
But BAP and QAP are on the same base AP and between same parallel straight lines BQ and AP
BAP=QAP...(iii)
ABOA=PQOP
Since PX is perpendicular to OA,
PX is the height of OAP and CAP
ar(OAP)=12bh=12×OA×PX
ar(CAP)=12bh=12×AC×PX
ar(CAP)ar(OAP)=ACOA=AB+ACOA=ABOA+BCOA....(iv)
Similarly, AY is perpendicular to OP.
So, AY is height of OAP and RAP
ar(RAP)ar(OAP)=12×RP×AY12×OP×AY=RPOP
=PQ+QROP=PQOP+QROP...(v)
But CAP and RAP are on the same base AP and between same parallel CR and AP. (CR||AP as l||n)
CAP=RAP...(vi)
From equations (iv), (v) and (vi), we get
ABOA+BCOA=PQOP+QROP
ABOA+BCOA=PQOP+BCOA
ABOA=PQOP
Dividing the equation by equation A,
ABOABCOA=PQOPQROP
ABBC=PQQR
The statement is true.


942897_179408_ans_dcbe524bc48f4b2f9774fd6cacc8344f.png

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