Question

State true or false:

In the given figure, $E$ is mid-point of $AB$ and $DE$ meets diagonal $AC$ at point $F$.
If $ABCD$ is a parallelogram and area of $△ADF$ is $60c{m}^2$

$DF:FE$ is 2:1

If true enter 1 else 0

Answer 1

ABCD is a parallelogram, DC is parallel to AB
So,$\angle CAB=\angle ACD$
$\angle AFE=\angle DFC$ (Vertical angles are always equal)
&, $\angle AFE=\angle DFC$
So,DFC EFA
$DF/FE=DC/AE$
$DC/\frac{1}{2}DC=2/1$