The correct option is A True
Given, the diagonals AC and BD intersect at point O such that OB=OD and AB∥DC.
Now, In △DOC and △AOB
∠BDC=∠DBA (Alternate angles, As AB∥CD and BD intersects it.)
OD=OB (Given)
∠DOC=∠AOB ( Vertically opposite angles)
So, △DOC≅△AOB (By ASA concurrence Property)
Since, Concurrent triangle have equal areas.
∴ Area of △DOC= Area of △AOB