O is a point inside the triangle ABC. Such that : ∠BOC=∠BAC+∠ABO+∠ACO
A
True
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B
False
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Solution
The correct option is A True In △ABC, ∠ABC+∠BAC+∠ACB=180 In △OBC, ∠BOC+∠OCB+∠OBC=180 Equating the two equations, ∠ABC+∠BAC+∠ACB=∠BOC+∠OCB+∠OBC ∠BOC=∠BAC+(∠ABC−∠OBC)+(∠ACB−∠OCB) ∠BOC=∠BAC+∠ABO+∠ACO