Question

State true or false:

Pythagorean triplet, whose one member is $14$, is $14,48,50$

• A. True
• B. False

Answer 1

The correct option is A True

$2k$, $(k^2+1)$ and $(k^2-1)$ form a Pythagorean triplet for any number, $k>1$
Let $2k=14$
Hence, $k=7$
and, $k^2+1=7^2+1=49+1=50$
and, $k^2-1=7^2-1=49-1=48$
Check the answers: ${14}^2+{48}^2=196+2304=2500={50}^2$
Hence, the triplet is $14,48,50$