Question

State true or false.

Rationalize:
$\frac{\sqrt{3}}{\sqrt{6}+\sqrt{3}}$
Answer: $16+6\sqrt{7}$

• A. True
• B. False

Answer 1

The correct option is B False

$\frac{\sqrt{3}}{\sqrt{6}+\sqrt{3}}$
Rationalizing the denominator,

$=\frac{\sqrt{3}(\sqrt{6}-\sqrt{3})}{(\sqrt{6}+\sqrt{3})\left(\right(\sqrt{6}-\sqrt{3}\left)\right)}$

$=\frac{\sqrt{18}-3}{6-3}$

$=\frac{3\sqrt{2}-3}{3}$

$=\sqrt{2}-1$