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Question

State True or False.
S and T are point on sides PR and QR of ∆PQR such that ∠P = ∠RTS.
Then, ∆RPQ ∼ ∆RTS.


A

30º

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B

40º

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Solution

The correct option is A

30º


In ∆RPQ and ∆RST,
∠RTS = ∠QPS (Given)
∠R = ∠R (Common angle)
Then,
∠Q = ∠RST
∴ ∆RPQ ∼ ∆RTS (By AAA similarity criterion)


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