Question

State True or False.

Simplify and express as positive indices:
$(x^n{y}^{-m}{)}^4.\times (x^3{y}^{-2}{)}^{-n}$, then answer is $\frac{x^n{y}^{2n}}{y^{4m}}=x^n{y}^{2n-4m}$.

• A. True
• B. False

Answer 1

The correct option is A True

$\Rightarrow (x^n{y}^{-m}{)}^4.\times (x^3{y}^{-2}{)}^{-n}$
$\Rightarrow x^{4n}{y}^{-4m}\times x^{-3n}{y}^{2n}$
$\Rightarrow \frac{x^n{y}^{2n}}{y^{4m}}\Rightarrow x^n{y}^{2n-4m}$