Question

State True or False.

$\sqrt{2}{x}^2+3x+\sqrt{2}=$$(\sqrt{2}x+1)(x+\sqrt{2})$

• A. True
• B. False

Answer 1

The correct option is A True

$\sqrt{2}{x}^2+3x+\sqrt{2}=\sqrt{2}{x}^2+2x+x+\sqrt{2}$
$=\sqrt{2}x(x+\sqrt{2})+1(x+\sqrt{2})$
$=(x+\sqrt{2})(\sqrt{2}x+1)$