Question

State true or false

$\sqrt{\frac{1}{4}}+{0.01}^{\frac{-1}{2}}-{27}^{\frac{2}{3}}=\frac{3}{2}$

• A. True
• B. False

Answer 1

The correct option is A True

$\sqrt{\frac{1}{4}}+(0.01{)}^{-\frac{1}{2}}-(27{)}^{\frac{2}{3}}$

$=\frac{1}{2}+(\frac{1}{0.01}{)}^{\frac{1}{2}}-(3{)}^{(}\frac{2\times 3}{3})$

$=\frac{1}{2}+\frac{1}{0.1}-3^2$

$=\frac{1}{2}+10-9$

$=\frac{1}{2}+1$

$=\frac{1+2}{1}$

$=\frac{3}{2}$