Sum of two sides of a triangle is greater than the third side.
A
True
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B
False
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Solution
The correct option is A True Let ABC be a triangle, We can extend BA past A into a straight line, Then there is a point D such that DA=CA Therefore, from Isosceles triangle has two equal angles, ∠ADC=∠ACD Thus, in △DCB, ∠BCD>∠BDC (Side opposite greater angle is larger) Thus, BD>CD BA+AD>CD (Since, AC=AD) BA+AC>CD