wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

State True or False:

The binding energy of a nucleus is the difference between the sum of the rest mass energies of each of its nucleons and the rest mass energy of the nucleus.


A
True
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
False
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A True

The energy (and equivalent rest mass according to E=mc2) of a bound system is less than the sum of its individual components, and the nucleus is nothing but a bound system of neutrons and protons! This simply means that you would have to put in some work (and corresponding energy) to separate the components of a bound system. Another way to look at it is that when the components of the nucleus are inside the nucleus they have more stability than as separate entities, making the nucleus a stable particle. (In general).
You can also think of it this way; the strong nuclear force being attractive in nature means that the closer you bring the nucleons, lesser will the energy associated with the system be! So, the difference in the sum of the energies of the nucleons (when they are isolated, infinitely far from each other) and that of the nucleus is the binding energy.


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Atomic Radius
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon