The figure obtained by joining the mid-points of the adjacent sides of a rectangle is a Trapezium
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Solution
Given: ABCD is a rectangle, M, N,S,T is the mid-point of AB,AD,DC,CB respectively Joint NS,ST,TM,MN, BD and AC. By Mid point theorem, NS∥MT∥AC and NS=MT=12AC MN∥ST∥BD and MN=ST=12BD Hence, MNST is a parallelogram. Since, opposite sides are equal and parallel. Now, AC=BD (Diagonals of rectangle are equal) Thus, MN=ST=NS=MT Hence, MNST is a rhombus. (Adjacent sides are also equal)