The correct option is A True
In △, BDC and BQR,
∠B=∠B (Common)
∠BDC=∠BQR (Corresponding angles of parallel lines)
∠BCD=∠BRQ (Corresponding angles of parallel lines)
thus, △BDC∼△BQR
Thus, BDQB=DCQR
2=DCQR (Q is the mid point of BD)
QR=12DC
Similarly, QP=12AB
Hence, QR+QP=12(AB+DC)
PR=12(AB+CD)