State true or false.
The length of the tangent drawn from a point 10 cm away from the center of a circle of radius 6 cm is 8 cm.

True

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

False

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
True

Given that AO = 10 cm, BO = 6 cm

Applying Pythagoras theorem

${A B}^{2} = {A O}^{2} - {B O}^{2}$

${A B}^{2} = 10^{2} - 6^{2}$

$\Rightarrow {A B}^{2} = 100 - 36 = 64$

$A B = 8$ cm

Suggest Corrections

Similar questions

State true or false.
The length of the tangent drawn from a point 10 cm away from the center of a circle of radius 6 cm is 8 cm.

The length of the tangent drawn from a point $8 c m$ away from the centre of a circle of radius $6 c m$ is $2 \sqrt{7} c m .$

Q. The length of the tangent drawn from a point

8

cm away from the centre of a circle of radius

6

cm is:

A point P is 10 cm away from the center of a circle. The length of the tangent drawn from P to the circle is 8 cm. The radius of the circle is equal to ____.

Q. From a point P, 10 cm away from the centre of a circle, a tangent PT of length 8 cm is drawn. Find the radius of the circle.

Join BYJU'S Learning Program

State true or false. The length of the tangent drawn from a point 10 cm away from the center of a circle of radius 6 cm is 8 cm.

The correct option is A True Given that AO = 10 cm, BO = 6 cm Applying Pythagoras theorem AB2=AO2–BO2 AB2=102–62 ⇒AB2=100–36=64 AB=8 cm

State true or false.
The length of the tangent drawn from a point 10 cm away from the center of a circle of radius 6 cm is 8 cm.

The correct option is A
True

Given that AO = 10 cm, BO = 6 cm

Applying Pythagoras theorem

${A B}^{2} = {A O}^{2} - {B O}^{2}$

${A B}^{2} = 10^{2} - 6^{2}$

$\Rightarrow {A B}^{2} = 100 - 36 = 64$

$A B = 8$ cm