Question

State True or False.

The order of shielding effect for different orbital is $s>p>d>f$.

• A. True
• B. False

Answer 1

The correct option is B False

The angular momentum quantum number $l$ takes integral values of zero up to $(n-1)$ where $n$ is the principal quantum number. So if $n=3$ then $l$ has values of $0,1$ and $2$. These correspond to the $s,p$ and $d$ orbitals. If you look at the normalized electron probability function plotted against distance from the nucleus you see that the lower the value of $l$ the greater the 'penetrating power' of the electron hence the greater shielding ability which is in the order $s>p>d$.
shielding effect is the reduction in effective nuclear charge on electron cloud due to differences in attraction between electrons and nucleus. It depends on many factors like size of atom, charge density, orbitals involved, effective nucleus charge. The size of $s$ and $p$ orbitals are very lesser than $d$ and $f$, due to that electron of $d$ and $f$ orbitals are spread in a large area and thus there are less effective shielding or poor shielding. structures of orbitals are also responsible for that.