Question

State True or False.

The rate of diffusion of methane is double the rate of diffusion of sulphur dioxide gas.

• A. True
• B. False

Answer 1

The correct option is A True

Applying Graham's law, $\frac{r_1}{r_2}=\sqrt{\frac{m_2}{m_1}}$, where $r_1$ & $r_2$ are rate of diffusion for methane & sulphur dioxide respectively and $m_1$ & $m_2$ are molar masses of methane & sulphur dioxide respectively.
$\therefore$$\frac{r_1}{r_2}=\sqrt{\frac{64}{16}}=\sqrt{\frac{4}{1}}=2$
$\therefore$ $r_1=2r_2$
Rate of diffusion of methane is twice as that of sulphur dioxide.