State True or False:
The sides of a triangle is $x^{2} - 3 x y + 8$ , $4 x^{2} + 5 x y - 3$ and $6 - 3 x^{2} + 4 x y$ , then its perimeter is $2 x^{2} + 6 x y + 11$ .

True

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False

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Solution

The correct option is A True
$P e r i m e t e r i s e q u a l t o t h e s u m o f s i d e s, W e c a n d i r e c t l y a d d t h e c o e f f i c i e n t s o f l i k e v a r i a b l e s, x^{2} - 3 x y + 8 + 4 x^{2} + 5 x y - 3 + 6 - 3 x^{2} + 4 x y = 2 x^{2} + 6 x y + 11$

The given statement is true.

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Similar questions

The sides of a triangle are $x^{2} - 3 x y + 8, 4 x^{2} + 5 x y - 3 a n d 6 - 3 x^{2} + 4 x y$ .Find its perimeter.

3 x^{2} + 5 x y - 4 y^{2} + x^{2} - 8 x y - 5 y^{2}

4 x^{2} - 3 x y - 9 y^{2}

2 x^{2} - 5 x y + 3 z^{2}

4 x y - x^{2} - z^{2}

2 x^{2} - 2 x y + 4 z^{m}

m

(2 x^{2} + 6 y + 3 x y), (3 x^{2} - 5 x y - x)

(6 x y + 5)

Thw teo adjacent sides of a rectangle are $2 x^{2} - 5 x y + 3 z^{2}$ and $4 x y - x^{2} - z^{2}$ .Find its perimeter.

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