Question

State true or false:

The supplement of the angle $(120+a-2b{)}^o$ is $(60-a+2b{)}^o$

• A. True
• B. False

Answer 1

The correct option is A True

Two angles are supplementary if their sum is ${180}^o$.

$\begin{array}{cc}{120}^o+a-2b+{60}^o-a+2b& =\left({120}^o+{60}^o\right)+\left(a-a\right)+\left(-2b+2b\right)\\ & ={180}^o\end{array}$

As the sum of the given angles is ${180}^o$ hence they are supplements of each other.