Question

State True or False.

The volume occupied by 32 g of oxygen is greater than that occupied by 16 g of methane, both being at the same T and P.

• A. True
• B. False

Answer 1

The correct option is B False

The volume occupied by 32 g of oxygen is equal to that occupied by 16 g of methane, both being at the same T and P.
The molar masses of oxygen and methane are 32 g/mol and 16 g/mol respectively.
The number of moles of oxygen are $\frac{32}{32}=1$. The number of moles of methane are $\frac{16}{16}=1$.
Since the number of moles of oxygen are equal to the number of moles of methane, there volumes are equal using PV$=$nRT