Two consecutive odd natural numbers such that the sum of their squares is 130 are 7 and 10.
A
True
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B
False
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Solution
The correct option is B False Let the numbers be (2n−1) and (2n+1) then, (2n−1)2+(2n+1)2=130 4n2−4n+1+4n2+1+4n=130 8n2=128 n2=16 n=±4 Neglect the negative value, n=4 The numbers are 7,9